document.write( "Question 223635: How many gallons of 70% antifreeze must be mixed with 120 gallons of 20% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #167160 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of 70% antifreeze must be mixed with 120 gallons of 20% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "---------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.70x + 0.20(120) = 0.40(x+120) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "70x + 20*120 = 40x + 40*120 \n" ); document.write( "30x = 20*120 \n" ); document.write( "x = 20*4 \n" ); document.write( "x = 80 gallons (amt. of 70% antifreeze needed for the mixture) \n" ); document.write( "================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |