document.write( "Question 223635: How many gallons of 70% antifreeze must be mixed with 120 gallons of 20% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #167160 by stanbon(75887)\"\" \"About 
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How many gallons of 70% antifreeze must be mixed with 120 gallons of 20% antifreeze to get a mixture that is 40% antifreeze?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.70x + 0.20(120) = 0.40(x+120)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "70x + 20*120 = 40x + 40*120
\n" ); document.write( "30x = 20*120
\n" ); document.write( "x = 20*4
\n" ); document.write( "x = 80 gallons (amt. of 70% antifreeze needed for the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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