document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=223544>Question 223544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the radius and diameter of a circle with an area of 35 in^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167121 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you find the radius and diameter of a circle with an area of 35 in^2\r<BR>\n" );
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document.write( "Step 1.  The Area A of a circles is given as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=pi%2Ar%5E2=pi%2A%28d%2F2%29%5E2=pi%2Ad%5E2%2F4 ALIGN=MIDDLE  ALT=\"A=pi%2Ar%5E2=pi%2A%28d%2F2%29%5E2=pi%2Ad%5E2%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > where r is the radius and d is the diameter.  Also diameter <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=2r ALIGN=MIDDLE  ALT=\"d=2r\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 2.  Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=pi%2Ar%5E2=35 ALIGN=MIDDLE  ALT=\"A=pi%2Ar%5E2=35\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 3.  Solving the equation in Step 2 leads to the following steps\r<BR>\n" );
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document.write( "Divide by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2=35%2Fpi ALIGN=MIDDLE  ALT=\"r%5E2=35%2Fpi\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Take the square root to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=sqrt%2835%2Fpi%29 ALIGN=MIDDLE  ALT=\"r=sqrt%2835%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=2sqrt%2835%2Fpi%29 ALIGN=MIDDLE  ALT=\"d=2sqrt%2835%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 4.  ANSWER:  Radius is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2835%2Fpi%29 ALIGN=MIDDLE  ALT=\"sqrt%2835%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and diameter is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Asqrt%2835%2Fpi%29 ALIGN=MIDDLE  ALT=\"2%2Asqrt%2835%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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