document.write( "Question 223490: Write an equation of the line having the given point and containing the given line.\r
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Algebra.Com's Answer #167109 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-8\" which goes through the point (\"6\",\"9\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-9=%28-8%29%28x-6%29\" Plug in \"m=-8\", \"x%5B1%5D=6\", and \"y%5B1%5D=9\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-9=-8x%2B%28-8%29%28-6%29\" Distribute \"-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-9=-8x%2B48\" Multiply \"-8\" and \"-6\" to get \"48\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-8x%2B48%2B9\" Add 9 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=-8x%2B57\" Combine like terms \"48\" and \"9\" to get \"57\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-8\" which goes through the point (\"6\",\"9\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=-8x%2B57\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-8\" and the y-intercept is \"b=57\"\r
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