document.write( "Question 29923: When given the problem, x + 5y = 15, How do I solve for y? \n" ); document.write( "
Algebra.Com's Answer #16709 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! When given the problem, x + 5y = 15, How do I solve for y? \n" ); document.write( "You are given a linear equation in x and y. \n" ); document.write( "You can express y as a function in x as follows: \n" ); document.write( "x + 5y = 15 ----(1) \n" ); document.write( "5y = -x+15 \n" ); document.write( "(taking x to the other side, the rule being change side then change sign.) \n" ); document.write( "Dividing by 5 \n" ); document.write( "y = (-1/5)x +3 ----(*) \n" ); document.write( "Note:A linear equation in x and y reperesents the equation to a straight line and the given equation: x + 5y-15=0 called the equation to a straight line in the general form is converted into the form (*) called the slope and the y-intercept form of equation to the line. \n" ); document.write( "When the coefficient of y on one side of the equation is 1, the coefficient of x on the other side gives the slope and the free constant on the other side gives the y-intercept. \n" ); document.write( "slope here is negative implies the straight line is making an obtuse angle with the x -axis and hence its journey is from the II quadrant to the fourth quadrant and since the y-intercept is positive,the journey is via the first quadrant.The line meets the y-axis at (0,3) at a point 3 units above the origin. \n" ); document.write( "Note: If you need not points on a whole line but one single point (x,y) then we must be furnished with one more linear equation in x and y such that the values for x and y hold in both the equations!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |