document.write( "Question 28954: I'm trying to help my son with this problem and I am stuck--please help!\r
\n" ); document.write( "\n" ); document.write( "A rectangle has an area of 2,040 square feet with base=60' and height=40'.\r
\n" ); document.write( "\n" ); document.write( "Inside this rectangle are two more rectangles--A & B. The area of A is twice the area of B. What is the area of each of these rectangles?\r
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Algebra.Com's Answer #16705 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
A rectangle has an area of 2,040 square feet with base=60' and height=40'.
\n" ); document.write( "Inside this rectangle are two more rectangles--A & B. The area of A is twice the area of B. What is the area of each of these rectangles?\r
\n" ); document.write( "\n" ); document.write( "The area of a rectangle = length X width = 60 ft X40ft = 2400 sqft
\n" ); document.write( "(AND NOT 2040)
\n" ); document.write( "What should be clearly stated in the problem is that the big rectangle of 2400 sqft area is split into two rectangles inside it called A and B. (that is to say A and B totally make up the space of this big rectangle should be the data)
\n" ); document.write( "Then we have A+B = 2040 ----(1)
\n" ); document.write( "And by data the area of A is twice the area of B.
\n" ); document.write( "That is A = 2B ----(2)
\n" ); document.write( "Putting (2) in (1)
\n" ); document.write( "(2B) + B = 2400
\n" ); document.write( "3B = 2400
\n" ); document.write( "B = 2400/3 = 800 ----(*)
\n" ); document.write( "Putting B = 800 in (2)
\n" ); document.write( "A = 2B = 2X(800) = 1600
\n" ); document.write( "Therefore the inner rectangle A is of area 1600 sqft and
\n" ); document.write( "the inner rectangle B is of area 800 sqft.
\n" ); document.write( "Verification: Of course these two rectangles add up to
\n" ); document.write( "(1600+800)=2400 the area of the big rectangle \r
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