document.write( "Question 223285: Solve this system of equation using substitution, 2x+y=3 x+2y=negetive3 \n" ); document.write( "
Algebra.Com's Answer #167042 by checkley77(12844)\"\" \"About 
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2x+y=3
\n" ); document.write( "x+2y=-3
\n" ); document.write( "x=-2y-3
\n" ); document.write( "Now replace x in the first equation by (-2y-3).
\n" ); document.write( "2(-2y-3)+y=3
\n" ); document.write( "-4y-6+y=3
\n" ); document.write( "-3y=3+6
\n" ); document.write( "-3y=9
\n" ); document.write( "y=9/-3
\n" ); document.write( "y=-3 ans.
\n" ); document.write( "2x-2=3
\n" ); document.write( "2x=3=3
\n" ); document.write( "2x=6
\n" ); document.write( "x=6/2
\n" ); document.write( "x=3 ans.
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