document.write( "Question 223285: Solve this system of equation using substitution, 2x+y=3 x+2y=negetive3 \n" ); document.write( "
Algebra.Com's Answer #167042 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2x+y=3 \n" ); document.write( "x+2y=-3 \n" ); document.write( "x=-2y-3 \n" ); document.write( "Now replace x in the first equation by (-2y-3). \n" ); document.write( "2(-2y-3)+y=3 \n" ); document.write( "-4y-6+y=3 \n" ); document.write( "-3y=3+6 \n" ); document.write( "-3y=9 \n" ); document.write( "y=9/-3 \n" ); document.write( "y=-3 ans. \n" ); document.write( "2x-2=3 \n" ); document.write( "2x=3=3 \n" ); document.write( "2x=6 \n" ); document.write( "x=6/2 \n" ); document.write( "x=3 ans. \n" ); document.write( " \n" ); document.write( " |