document.write( "Question 223170: A light bulb manufacturer claims his light bulbs will last 500 hours on the average. The lifetime of a light bulb is assumed to follow an exponential distribution.
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document.write( "a. What is the probability that the light bulb will have to replaced within 500 hours?
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document.write( "b. What is the probability that the light bulb will last more than 1000 hours?
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document.write( "c. What is the probability that the light bulb will last between 200 and 800 hours?
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Algebra.Com's Answer #167041 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A light bulb manufacturer claims his light bulbs will last 500 hours on the average. The lifetime of a light bulb is assumed to follow an exponential distribution. \n" ); document.write( "a. What is the probability that the light bulb will have to replaced within 500 hours? \n" ); document.write( "--- \n" ); document.write( "lamda = 1/500 \n" ); document.write( "Ans: P(x<=500) = 1 - e^(-lamda*x) = 1-e^[(-1/500)*500] = 1-e^-1 = 0.6321\r \n" ); document.write( "\n" ); document.write( "---------------------------------- \n" ); document.write( "b. What is the probability that the light bulb will last more than 1000 hours? \n" ); document.write( "Ans:P(x>=1000) = 1 - P(x<=1000) = 1 -[1-e^(-1/500*1000) \n" ); document.write( "= 1 -[1-e^(-2)] = e^(-2) = 0.1353 \n" ); document.write( "----------------------------------\r \n" ); document.write( "\n" ); document.write( "c. What is the probability that the light bulb will last between 200 and 800 hours? \n" ); document.write( "Answer will be P(x<=800)-P(x<=200) \n" ); document.write( "Remember P(x<=k) = 1-e^(-lambda*k) \n" ); document.write( "I'll leave that to you. \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |