document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29922>Question 29922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you check my work.  I was asked to simplify this equation.  Thanks for your help.\r<BR>\n" );
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document.write( "5XY/X + 6Y^/Y - 5(X - Y)<BR>\n" );
document.write( "5Y + 6Y - 5X + 5Y<BR>\n" );
document.write( "11Y - 5X + 5Y<BR>\n" );
document.write( "16Y - 5X  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16704 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are right and congratulations!<BR>\n" );
document.write( "Let us look into the steps involved\r<BR>\n" );
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document.write( "5XY/X + 6Y^2/Y - 5(X - Y) <BR>\n" );
document.write( "=5Y + 6Y - 5X + 5Y (caneling X in the first term fraction,Y in the second term fraction and expanding the bracket)<BR>\n" );
document.write( "=(5Y + 6Y) - 5X + 5Y  (by additive associativity)<BR>\n" );
document.write( "=11Y - 5X + 5Y<BR>\n" );
document.write( "=11y+5y-5x  (by additive commutativity)<BR>\n" );
document.write( "=(11y+5y)-5x  <BR>\n" );
document.write( "=16Y - 5X <BR>\n" );
document.write( "Note: You have understood the problem. THAT IS FINE. In the second fraction the power is missing. Looking at your answer I think it is 2<BR>\n" );
document.write( "If you are asked to carry out such a simple work that means it is required of you to give the algebraic steps involved.<BR>\n" );
document.write( "All the best<BR>\n" );
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