document.write( "Question 223211: Sigh! I just don't get this stuff : ( Very frustrating. Please help.\r
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document.write( "A boat can maintain a speed of 16mph. The boat makes a trip upstream in 20 mins. The return trip takes 15 minutes. What is the speed of the current? \n" );
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Algebra.Com's Answer #166981 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A boat can maintain a speed of 16mph. \n" ); document.write( "The boat makes a trip upstream in 20 mins. \n" ); document.write( " The return trip takes 15 minutes. What is the speed of the current? \n" ); document.write( ": \n" ); document.write( "Change min to hrs: \n" ); document.write( "15 min = 15/60 = 1/4 hr \n" ); document.write( "20 min = 20/60 = 1/3 hr \n" ); document.write( ": \n" ); document.write( "Let c = speed of the current \n" ); document.write( "then we can say: \n" ); document.write( "(16 - c) = boat speed up stream \n" ); document.write( "and \n" ); document.write( "(16 + c) = boat speed down stream \n" ); document.write( ": \n" ); document.write( "The distance up and the distance back are equal. Write a distance equation \n" ); document.write( "Dist = time * speed \n" ); document.write( "; \n" ); document.write( "Up dist = down dist \n" ); document.write( " \n" ); document.write( "Multiply both sides by 12 to get rid of those denominators \n" ); document.write( "4(16-c) = 3(16+c) \n" ); document.write( "64 - 4c = 48 + 3c \n" ); document.write( "64 - 48 = 3c + 4c \n" ); document.write( "16 = 7c \n" ); document.write( "c = \n" ); document.write( "c = 2.2587 mph speed of the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can confirm this solution by finding the distance of each, should be equal \n" ); document.write( ".25(16 + 2.2587) = 4.57 miles \n" ); document.write( ".33(16 - 2.2587) = 4.57 miles \n" ); document.write( " |