document.write( "Question 223169: please help me solve simplify: \"sqrt+%2840x%5E2%29+%2A+sqrt+%2810x%29+\" \n" ); document.write( "
Algebra.Com's Answer #166920 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt+%2840x%5E2%29+%2A+sqrt+%2810x%29+\"
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document.write( "First take the square root of \"x%5E2\" \r\n" );
document.write( "in the first factor, which gives x in front\r\n" );
document.write( "of the first radical \r\n" );
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document.write( "\"x%2Asqrt+%2840%29+%2A+sqrt+%2810x%29+\"\r\n" );
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document.write( "Multiply under the radicals and form just one\r\n" );
document.write( "radical:\r\n" );
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document.write( "\"x%2Asqrt+%28400x%29+\"\r\n" );
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document.write( "Now take the square root of the \"400\" which\r\n" );
document.write( "gives \"20\" in front of the radical.\r\n" );
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document.write( "\"20x%2Asqrt%28x%29+\"\r\n" );
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document.write( "Edwin
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