document.write( "Question 222747: It has been estimated that 900 curies of a radioactive substance introduced at a point on the surface of the open sea would spread over an area of 24000km^2 in 30 days. Assuming that the area covered by the radioactive substance is a linear function of time t and is always circular in shape, express the radius r of the contamination as a function of t.\r
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\n" ); document.write( "\n" ); document.write( "I worked it out and got r=((sqr(24000/pi))/(30))*t. It appears that this is not right though. Please explain what I am doing wrong.
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Algebra.Com's Answer #166905 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
It has been estimated that 900 curies of a radioactive substance introduced at
\n" ); document.write( " a point on the surface of the open sea would spread over an area of 24000km^2 in 30 days.
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\n" ); document.write( "Assuming that the area covered by the radioactive substance is a linear function of time t and
\n" ); document.write( " is always circular in shape, express the radius r of the contamination as a function of t.
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\n" ); document.write( "Do not simplify the number under the radical.
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\n" ); document.write( "I think what you got is pretty close, here's my take on this
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\n" ); document.write( "Find the value of r when t = 30 days and area = 24000
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\n" ); document.write( "\"pi%2A%2830r%29%5E2+=+24000\"
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\n" ); document.write( "\"pi%2A900%2Ar%5E2+=+24000\"
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\n" ); document.write( "\"r%5E2+=+24000%2F%28900%2Api%29\"
\n" ); document.write( "Reduce the fraction
\n" ); document.write( "\"r%5E2+=+80%2F%283%2Api%29\"
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\n" ); document.write( "\"r+=+sqrt%2880%2F%283pi%29%29\"
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\n" ); document.write( "r as a function of t
\n" ); document.write( "\"r+=+sqrt%2880%2F%283pi%29%29%2At\"
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\n" ); document.write( "Check this find radius when t = 30 days
\n" ); document.write( "\"r+=+sqrt%2880%2F%283pi%29%29%2A30\"
\n" ); document.write( "r = 87.4 km
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\n" ); document.write( "Find the area using this value for r
\n" ); document.write( "A = pi*87.4^2 = 24,000 sq/km; confirms our solution
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