document.write( "Question 223004: Here is the problem using natural logarithm:
\n" ); document.write( "23=3ln(x-1)+14\r
\n" ); document.write( "\n" ); document.write( "What we did was the following:
\n" ); document.write( "23=3ln(x-1)+14
\n" ); document.write( "subtract 14 from both sides
\n" ); document.write( "9=3ln(x-1)
\n" ); document.write( "divide both sides by 3
\n" ); document.write( "3=ln(x-1)
\n" ); document.write( "x-1=e^3
\n" ); document.write( "add 1 to both sides
\n" ); document.write( "x=e^3+1 \r
\n" ); document.write( "\n" ); document.write( "Please help!!! It's driving us nuts!!
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Algebra.Com's Answer #166846 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If the original problem is \"23=3ln%28x-1%29%2B14\" and your answer is \"x=e%5E3%2B1\", then you are correct.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "\"23=3ln%28x-1%29%2B14\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"23=3ln%28e%5E3%2B1-1%29%2B14\" Plug in \"x=e%5E3%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"23=3ln%28e%5E3%29%2B14\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"23=3%2A3ln%28e%29%2B14\" Pull down the exponent.\r
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\n" ); document.write( "\n" ); document.write( "\"23=3%2A3%281%29%2B14\" Evaluate the natural log of 'e' to get 1.\r
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\n" ); document.write( "\n" ); document.write( "\"23=9%2B14\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"23=23\" Add. Since the equation is true, this verifies the solution.
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