document.write( "Question 222953: At Euclid High School, the number of students taking the AMC10 was 60 in
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document.write( "2002, 66 in 2003, 70 in 2004, 76 in 2005, and 78 in 2006, and is 85 in 2007.
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document.write( "Between what two consecutive years was there the largest percentage increase?\r
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document.write( "(A) 2002 and 2003 (B) 2003 and 2004 (C) 2004 and 2005 (D) 2005 and 2006\r
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document.write( "(E) 2006 and 2007 \n" );
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Algebra.Com's Answer #166834 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 60 = 2002 \n" ); document.write( "66 = 2003 \n" ); document.write( "70 = 2004 \n" ); document.write( "76 = 2005 \n" ); document.write( "78 = 2006 \n" ); document.write( "85 = 2007\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "rate of increase for each year would be the value in that year minus the value in the previous year divided by the value in the previous year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "rate of increase in 2003 over 2002 = 6/60 = .1 \n" ); document.write( "rate of increase in 2004 over 2003 = 4/66 = .06 \n" ); document.write( "rate of increase in 2005 over 2004 = 6/70 = .085 \n" ); document.write( "rate of increase in 2006 over 2005 = 2/76 = .026 \n" ); document.write( "rate of increase in 2007 over 2006 = 7/78 = .089\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "percent equals 1005 * rate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "biggest increase percent is 2003 over 2002 = 10%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |