document.write( "Question 222956: Can someone please help me understand how to solve this problem. Thank you in advance.\r
\n" ); document.write( "\n" ); document.write( "Area of a painting.\r
\n" ); document.write( "\n" ); document.write( "A rectangular painting with a width of X centimeters has an area of x^2 + 50x square centimeters. Find a binomial that represents the length.
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Algebra.Com's Answer #166824 by Theo(13342)\"\" \"About 
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A rectangular painting with a width of X centimeters has an area of x^2 + 50x square centimeters. Find a binomial that represents the length. \r
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\n" ); document.write( "\n" ); document.write( "Area equals length * width.\r
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\n" ); document.write( "\n" ); document.write( "you have the area equal to x^2 + 50x\r
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\n" ); document.write( "\n" ); document.write( "If you let x = width, and y = length, then you get:\r
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\n" ); document.write( "\n" ); document.write( "area = x*y = x^2 + 50x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by x to get:\r
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\n" ); document.write( "\n" ); document.write( "y = (x^2 + 50x) / y = x+50\r
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\n" ); document.write( "\n" ); document.write( "your answer should be:\r
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\n" ); document.write( "\n" ); document.write( "y = x+50\r
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\n" ); document.write( "\n" ); document.write( "if that's true, then x * (x+50) = x*y = area of the painting.\r
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\n" ); document.write( "\n" ); document.write( "x * (x+50) = x^2 + 50x so answer should be good.\r
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