document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222864>Question 222864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the measure of an angle that is one fourth as large as its supplement </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166770 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the measure of an angle that is one fourth as large as its supplement.\r<BR>\n" );
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document.write( "Step 1.  Supplementary angles means two angles add up to 180 degrees.\r<BR>\n" );
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document.write( "Step 2.  Let x be the angle.\r<BR>\n" );
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document.write( "Step 3.  Let 180-x be the supplementary angle.\r<BR>\n" );
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document.write( "Step 4.  Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28180-x%29%2F4 ALIGN=MIDDLE  ALT=\"x=%28180-x%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > since the measure of an angle that is one fourth as large as its supplement.\r<BR>\n" );
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document.write( "Step 5.  Solving the equation in Step 4 yields the following steps.\r<BR>\n" );
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document.write( "Multiply 4 to both sides to get rid of the denominator\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x=4%28180-x%29%2F4 ALIGN=MIDDLE  ALT=\"4x=4%28180-x%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x=180-x ALIGN=MIDDLE  ALT=\"4x=180-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Add x to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%2Bx=180-x%2Bx ALIGN=MIDDLE  ALT=\"4x%2Bx=180-x%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x=180 ALIGN=MIDDLE  ALT=\"5x=180\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide 5 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2F5=180%2F5 ALIGN=MIDDLE  ALT=\"5x%2F5=180%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=36 ALIGN=MIDDLE  ALT=\"x=36\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-x=144 ALIGN=MIDDLE  ALT=\"180-x=144\"   DISABLED_style= \"max-width:90%; height:auto;\" > where 36 is one-fourth of 144.\r<BR>\n" );
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document.write( "Step 6.  ANSWER:  The angle is 36 degrees.\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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document.write( " </SPAN>\n" );
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