document.write( "Question 222610: Two cars left Daisy's diner at the same time and traveled in opposite directions. One car traveled for 78 minutes. The other car traveled for 144 minutes at a rate 5 km/h faster than the first car. If the faster car went twice as far as the slower car, how far did each travel? \n" ); document.write( "
Algebra.Com's Answer #166762 by ankor@dixie-net.com(22740)\"\" \"About 
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One car traveled for 78 minutes.
\n" ); document.write( "The other car traveled for 144 minutes at a rate 5 km/h faster than the first car.
\n" ); document.write( "If the faster car went twice as far as the slower car, how far did each travel?
\n" ); document.write( ":
\n" ); document.write( "convert 78 min to hrs: 78/60 = 1.3 hrs
\n" ); document.write( "convert 144 min to hrs: 144/60 = 2.4 hrs
\n" ); document.write( ":
\n" ); document.write( "Find the speed of the cars
\n" ); document.write( "Let s = speed of the 1st car
\n" ); document.write( "then
\n" ); document.write( "(s+5) = speed of the 2nd car
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = time * speed
\n" ); document.write( ":
\n" ); document.write( "car 2 dist = twice car 1 dist
\n" ); document.write( "2.4(s+5) = 2*(1.3s)
\n" ); document.write( "2.4s + 12 = 2.6s
\n" ); document.write( "12 = 2.6s - 2.4s
\n" ); document.write( "12 = .2s
\n" ); document.write( "s = \"12%2F.2\"
\n" ); document.write( "s = 60 km/h speed of car 1
\n" ); document.write( "and
\n" ); document.write( "65 km/h speed of car 2
\n" ); document.write( ":
\n" ); document.write( "Find the distances:
\n" ); document.write( "Car 1: 60 * 1.3 = 78 km
\n" ); document.write( "Car 2: 65 * 2.4 = 156km (twice as far)
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