document.write( "Question 222840: I really need help setting up the equation to solve the following problem more than anything. Once I get there, hopefully I will be able to get it. Could you please help me set up the following word problem?\r
\n" ); document.write( "\n" ); document.write( "2 trains leave the depot at the same time, one traveling north and the other south. The speed of one train is 15 MPH slower than the other. If after 3 hours, the distance between trains is 315 miles, what is the speed of each train?\r
\n" ); document.write( "\n" ); document.write( "all I can think of is, ( x= y-15) but I'm not even sure if that's correct.
\n" ); document.write( "

Algebra.Com's Answer #166748 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2 trains leave the depot at the same time, one traveling north and the other south. The speed of one train is 15 MPH slower than the other. If after 3 hours, the distance between trains is 315 miles, what is the speed of each train?
\n" ); document.write( "----------------------------------
\n" ); document.write( "1st train DATA:
\n" ); document.write( "rate = x-15 mph ; time = 3 hrs. ; distance = rt = 3(x-15) miles
\n" ); document.write( "----------------------------------------
\n" ); document.write( "2nd train DATA:
\n" ); document.write( "rate = x mph ; time = 3 hrs. ; distance = rt = 3x
\n" ); document.write( "--------------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "distance + distance = 315 miles
\n" ); document.write( "3(x-15)+3x = 315
\n" ); document.write( "6x - 45 = 315
\n" ); document.write( "6x = 360
\n" ); document.write( "x = 60 mph (speed of the faster train)
\n" ); document.write( "x-15 = 45 mph (speed of the slower train)
\n" ); document.write( "=============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );