document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222800>Question 222800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the degree measure of an angle whose complement is 25 percent of its supplement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166739 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the degree measure of an angle whose complement is 25 percent of its supplement.\r<BR>\n" );
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document.write( "Step 1.  Complementary angles means two angles add up 90 degrees.\r<BR>\n" );
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document.write( "Step 2. Supplementary angles means two angles add up 180 degrees.\r<BR>\n" );
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document.write( "Step 3.  Let x be the angle\r<BR>\n" );
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document.write( "Step 4.  Let 90-x be the complementary angle\r<BR>\n" );
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document.write( "Step 5.  Let 180-x be the supplementary angle.\r<BR>\n" );
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document.write( "Step 6.  Let 25% be 1/4=0.25 by definition\r<BR>\n" );
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document.write( "Step 7.  Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-x=%28180-x%29%2F4 ALIGN=MIDDLE  ALT=\"90-x=%28180-x%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > since measure of an angle whose complement is 25 percent of its supplement.\r<BR>\n" );
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document.write( "Step 8.  Solving equation in Step 7 yields the following steps...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-x=%28180-x%29%2F4 ALIGN=MIDDLE  ALT=\"90-x=%28180-x%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "Multiply by 4 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2890-x%29=180-x ALIGN=MIDDLE  ALT=\"4%2890-x%29=180-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360-4x=180-x ALIGN=MIDDLE  ALT=\"360-4x=180-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Add 4x-180 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360-4x%2B4x-180=180-x%2B4x-180 ALIGN=MIDDLE  ALT=\"360-4x%2B4x-180=180-x%2B4x-180\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180=3x ALIGN=MIDDLE  ALT=\"180=3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide by 3 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180%2F3=3x%2F3 ALIGN=MIDDLE  ALT=\"180%2F3=3x%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=60 ALIGN=MIDDLE  ALT=\"x=60\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-x=30 ALIGN=MIDDLE  ALT=\"90-x=30\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-60=120 ALIGN=MIDDLE  ALT=\"180-60=120\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the complementary angle of 30 degrees is equal to 25 percent of the supplementary angle of 120 degrees\r<BR>\n" );
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document.write( "Step 9.  ANSWER:  The angle is 60 degrees.\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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document.write( " </SPAN>\n" );
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