document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222804>Question 222804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the Dicovering Algebra: An Investigative approach, there is a question that says Find the value of the unknown number in each proportion? The problem is 52/91=42/s. So do i inverse it. Swich it up like this: 91/52=s/42? or keep it the same? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166733 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of the unknown number in each proportion? The problem is 52/91=42/s. So do i inverse it. Swich it up like this: 91/52=s/42? or keep it the same?<BR>\n" );
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document.write( "91/52=42/s<BR>\n" );
document.write( "You want to get s by itself on one side of the equal sign.<BR>\n" );
document.write( "You don't invert anything in equations.<BR>\n" );
document.write( "A shortcut is to cross multiply.  Multiply each NUM by the DEN of the other fraction.<BR>\n" );
document.write( "91s = 52*42<BR>\n" );
document.write( "Then divide by 91<BR>\n" );
document.write( "s = 52*42/91<BR>\n" );
document.write( "Then reduce the fraction<BR>\n" );
document.write( "s = 4*42/7<BR>\n" );
document.write( "s = 4*6<BR>\n" );
document.write( "s = 24<BR>\n" );
document.write( " </SPAN>\n" );
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