document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222797>Question 222797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car's radiator contains 12L of antifreeze at 25% concentration. How many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166729 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car's radiator contains 12L of antifreeze at 25% concentration. How many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = amount removed and replaced w/pure antifreeze<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x + .25(12-x) = .50(12)<BR>\n" );
document.write( "x + 4 - .25x = 6<BR>\n" );
document.write( "x - .25x = 2<BR>\n" );
document.write( ".75x = 2<BR>\n" );
document.write( "x = 2/.75<BR>\n" );
document.write( "x = 2.67 liters<BR>\n" );
document.write( " </SPAN>\n" );
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