document.write( "Question 222775: The formula s=-16t^2 + vt + s gives you the height in feet above the earth at time t seconds for an object projected into the air with an initial velocity of v feet per second (ft/sec) from an initial height of s feet. Two balls are thrown into the sir simultaneously, one from the ground at 40 ft/sec and one from a height of 20 feet at 30 ft/sec. For what values of t will their heights above the ground differ by 10 feet or less? \n" ); document.write( "
Algebra.Com's Answer #166719 by stanbon(75887)\"\" \"About 
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The formula s=-16t^2 + vt + s gives you the height in feet above the earth at time t seconds for an object projected into the air with an initial velocity of v feet per second (ft/sec) from an initial height of s feet.
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\n" ); document.write( "Two balls are thrown into the sir simultaneously, one from the ground at 40 ft/sec and one from a height of 20 feet at 30 ft/sec.
\n" ); document.write( "1st ball: s(t) = -16t^2+40t+0
\n" ); document.write( "2nd ball: s(t) = -16t^2+30t+20
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\n" ); document.write( "\n" ); document.write( " For what values of t will their heights above the ground differ by 10 feet or less?
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\n" ); document.write( "Equation:
\n" ); document.write( "height - height <= 10 feet
\n" ); document.write( "(-16t^2+30t+20) - (-16t^2+40t) <= 10
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\n" ); document.write( "-10t+20 <= 10
\n" ); document.write( "-10t <= -10
\n" ); document.write( "t >= 1 second (the heights will differ by at least 10 ft after the 1st second
\n" ); document.write( "and until one of the balls reaches the ground.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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