document.write( "Question 222738: square root of 72x^2 y^3
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Algebra.Com's Answer #166712 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2872%2Ax%5E2%2Ay%5E3%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2836%2A2%2Ax%5E2%2Ay%5E3%29\" Factor \"72\" into \"36%2A2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2836%2A2%2Ax%5E2%2Ay%5E2%2Ay%29\" Factor \"y%5E3\" into \"y%5E2%2Ay\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2836%29%2Asqrt%282%29%2Asqrt%28x%5E2%29%2Asqrt%28y%5E2%29%2Asqrt%28y%29\" Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"6%2Asqrt%282%29%2Asqrt%28x%5E2%29%2Asqrt%28y%5E2%29%2Asqrt%28y%29\" Take the square root of \"36\" to get \"6\".\r
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\n" ); document.write( "\n" ); document.write( "\"6%2Asqrt%282%29%2Ax%2Asqrt%28y%5E2%29%2Asqrt%28y%29\" Take the square root of \"x%5E2\" to get \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"6%2Asqrt%282%29%2Ax%2Ay%2Asqrt%28y%29\" Take the square root of \"y%5E2\" to get \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"6xy%2Asqrt%282y%29\" Rearrange and multiply the terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2872%2Ax%5E2%2Ay%5E3%29\" simplifies to \"6xy%2Asqrt%282y%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2872%2Ax%5E2%2Ay%5E3%29=6xy%2Asqrt%282y%29\" where every variable is non-negative.
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