document.write( "Question 222631: 3x/4 +11 = 22-5
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Algebra.Com's Answer #166673 by Valley11(1)\"\" \"About 
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\n" ); document.write( "subtract 5 from 22 on the right side.
\n" ); document.write( "3x/4 +11=17
\n" ); document.write( "Subtract 11 from both sides
\n" ); document.write( "3x/4=6\r
\n" ); document.write( "\n" ); document.write( "multiply each side by 4 to get rid of the fraction
\n" ); document.write( "3x=24
\n" ); document.write( "divide by 3 on each side
\n" ); document.write( "x=8
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