document.write( "Question 222574: how much water should be added to 1 gallon of pure antifreeze to obtain a solution of 95% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #166622 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Let x = amt of pure water added (0% antifreeze) \n" ); document.write( ". \n" ); document.write( "(0 %) x + 1(100%) = (1+x)(95%) \n" ); document.write( ". \n" ); document.write( "0*x + 1+1.00 = .95 +.95x \n" ); document.write( ". \n" ); document.write( "1=.95 +.95x \n" ); document.write( ". \n" ); document.write( ".05 = .95x \n" ); document.write( ". \n" ); document.write( ".053 = x,,,, in gallons \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Check \n" ); document.write( ". \n" ); document.write( "0(.053) +1 = .95(1.053)= 1,,,,,ok \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |