document.write( "Question 222574: how much water should be added to 1 gallon of pure antifreeze to obtain a solution of 95% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #166622 by RAY100(1637)\"\" \"About 
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Let x = amt of pure water added (0% antifreeze)
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\n" ); document.write( "(0 %) x + 1(100%) = (1+x)(95%)
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\n" ); document.write( "0*x + 1+1.00 = .95 +.95x
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\n" ); document.write( "1=.95 +.95x
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\n" ); document.write( ".05 = .95x
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\n" ); document.write( ".053 = x,,,, in gallons
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\n" ); document.write( "0(.053) +1 = .95(1.053)= 1,,,,,ok
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