document.write( "Question 222556: Calculate the following equation.\r
\n" ); document.write( "\n" ); document.write( "10000=500(1+R/100)^25\r
\n" ); document.write( "\n" ); document.write( "I know that this question seems really simple, but actually I don't know the way to calculate it. So I request you to explain me everything in details.It would be a great pleasure for me. Thankyou very much indeed. \n" ); document.write( "

Algebra.Com's Answer #166619 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
10000 = 500(1+R/100)^25
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\n" ); document.write( "rewrite the equation to
\n" ); document.write( "500(1 + .01R)^25 = 10000
\n" ); document.write( ":
\n" ); document.write( "Divide both sides by 500
\n" ); document.write( "(1 + .01R)^25 = 20
\n" ); document.write( ":
\n" ); document.write( "Use logs
\n" ); document.write( "25*log(1 + .01R) = log(20)
\n" ); document.write( ":
\n" ); document.write( "log(1 + .01R) = $\"1.30103%2F25\"$
\n" ); document.write( "log(1 + .01R) = .05204
\n" ); document.write( ":
\n" ); document.write( "Find the 10^x (antilog)
\n" ); document.write( "1 + .01R = 1.1273
\n" ); document.write( ":
\n" ); document.write( ".01R = 1.1273 - 1
\n" ); document.write( ".01R = .1273
\n" ); document.write( ":
\n" ); document.write( "Multiply both sides by 100
\n" ); document.write( "R = 12.73
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\n" ); document.write( ":
\n" ); document.write( "Check solution on calc: enter: 500(1+(12.73/100))^25 = 9999 ~ 10000 \n" ); document.write( "

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