document.write( "Question 222527: determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value\r
\n" ); document.write( "\n" ); document.write( "f(x) = 2xsquared + 2x - 6
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Algebra.Com's Answer #166617 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+2x%5E2+%2B+2x+-+6+\"
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\n" ); document.write( "From the coefficient associated with the x^2 term, in this case, it's a POSITIVE TWO. Since it is \"positive\" think \"smiley face\"-- so, it's a parabola that's opens upwards. If it was \"negative\" think \"sad face\" -- so, it's a parabola that's opens downwards.
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\n" ); document.write( "Since the coefficient is +2, it opens upwards thus the function will have a MINIMUM.
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\n" ); document.write( "One way to find the vertex, is by completing the square. Doing so you will get it into the \"vertex form\" of the equation:
\n" ); document.write( "y= a(x-h)2+k
\n" ); document.write( "where
\n" ); document.write( "(h,,k) is the vertex
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\n" ); document.write( "\"f%28x%29+=+2x%5E2+%2B+2x+-+6+\"
\n" ); document.write( "\"f%28x%29+=+2%28x%5E2+%2B+x+%2B+__%29++-+6+\"
\n" ); document.write( "\"f%28x%29+=+2%28x%5E2+%2B+x+%2B+1%2F4+%29++-+6+-+1%2F2\"
\n" ); document.write( "\"f%28x%29+=+2%28x+%2B+1%2F2%29%5E2++-+13%2F2+\"
\n" ); document.write( "\"f%28x%29+=+2%28x+-+%28-1%2F2%29%29%5E2++%2B+%28-13%2F2%29\"
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\n" ); document.write( "Therefore, the vertex is at (-1/2, -13/2)
\n" ); document.write( "or
\n" ); document.write( "(-.5, -6.5)\r
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