document.write( "Question 29896: I need help finding the point of intersection for 6x-2y=10, and 3x-5=y. \n" ); document.write( "

Algebra.Com's Answer #16661 by Cintchr(481) $\"\"$ $\"About$

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$\"+6x-2y=10+\"$ and $\"+3x-5=y+\"$ since the second equation is already solved for y I will use substitution.
\n" ); document.write( " $\"+6x-2y=10+\"$ plug in the second equation $\"+3x-5+\"$ for y
\n" ); document.write( " $\"+6x-2%283x-5%29=10+\"$ distribute the 2 watch your signs!!
\n" ); document.write( " $\"+6x-6x%2B10=10+\"$ combine like terms
\n" ); document.write( " $\"+10+=+10+\"$ We know this to be a true statement, but does not answer what the point of intersection is, so let's look at the first equation again.
\n" ); document.write( " $\"+6x-2y=10+\"$ all numbers are divisable by 2 ... lets divide.
\n" ); document.write( " $\"+6x%2F2-2y%2F2=10%2F2+\"$
\n" ); document.write( " $\"+3x-5=y+\"$ But that is the second equation. So that means that they are in fact the exact same line, and have an infinite number of solutions. \n" ); document.write( "

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