document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222478>Question 222478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What weight of an alloy containing 10% silver must be melted with an alloy containing 60% silver to obtain 10 lb of an alloy containing 40% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166576 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What weight of an alloy containing 10% silver must be melted with an alloy containing 60% silver to obtain 10 lb of an alloy containing 40% silver?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "silver + silver = silver<BR>\n" );
document.write( "0.10x + 0.60(10-x) = 0.40(10)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "10x + 60*10 - 60x = 40*10<BR>\n" );
document.write( "-50x = -20*10<BR>\n" );
document.write( "x = 4 lbs. (amount of 10% alloy needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );