document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222452>Question 222452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lenght of a retangle is 3 cm longer than twice the width.the area of the retangle is 90 cm ^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166558 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"The lenght of a retangle is 3 cm longer than twice the width\" --> L=2W+3\r<BR>\n" );
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document.write( "A=LW=(2W+3)(W)=90\r<BR>\n" );
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document.write( "2W^2+3W=90\r<BR>\n" );
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document.write( "2W^2+3W-90=0\r<BR>\n" );
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document.write( "(W-6)(2W+15)=0\r<BR>\n" );
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document.write( "W=6 or W=-15/2 ---> L=2(6)+3=15\r<BR>\n" );
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document.write( "Answer: width = 6, length = 15 </SPAN>\n" );
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