document.write( "Question 222215: 1/2x+ (-1/2)y=1/2
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document.write( "(-1/3)x+(-3/4)y=2\r
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document.write( "I divided everything by 1/2 and you get x-y=1 for the first equation.
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document.write( "the second equation i times everything by 12 and get (-4)x + (-9)y = 24
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document.write( "multiply the first equation by -9, so we get -9x +9y = -9.
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document.write( "(-9)x + (9)y = -9
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document.write( "(-4)x + (-9)y = 24
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document.write( "I get (-15/13, -28/13)\r
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document.write( "But it is wrong, what did i do wrong? Thanks for the help! \n" );
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Algebra.Com's Answer #166467 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1/2x+ (-1/2)y=1/2 \n" ); document.write( "(-1/3)x+(-3/4)y=2 \n" ); document.write( "----------------------------- \n" ); document.write( "Multiply thru 1st by 2 \n" ); document.write( "Multiply thru 2nd by -12 \n" ); document.write( "------------------------------- \n" ); document.write( "x - y = 1 \n" ); document.write( "4x +9y = -24 \n" ); document.write( "--- \n" ); document.write( "Multiply thru 1st by 4 \n" ); document.write( "---------------------------- \n" ); document.write( "4x - 4y = 4 \n" ); document.write( "4x + 9y = -24 \n" ); document.write( "---------------- \n" ); document.write( "Subtract 1st from 2nd and solve for \"y\": \n" ); document.write( "13y = -28 \n" ); document.write( "y = -28/13 \n" ); document.write( "----- \n" ); document.write( "Substitute into x - y = 1 to solve for \"x\": \n" ); document.write( "x +(28/13) = 1 \n" ); document.write( "x = (13/13)-(28/13) \n" ); document.write( "x = -15/13 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |