document.write( "Question 29878: A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? \n" ); document.write( "
Algebra.Com's Answer #16646 by Earlsdon(6294)\"\" \"About 
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First calculate the area of the rectangle using the given dimensions, L = 12\" and W = 8\"
\n" ); document.write( "A = L*W
\n" ); document.write( "A = 12*8 = 96 sq.in.\r
\n" ); document.write( "\n" ); document.write( "Now, the area of a triangle is given by:
\n" ); document.write( "\"A+=+%281%2F2%29bh\" and this area is = 96 sq.in., so you can write:
\n" ); document.write( "\"%281%2F2%29bh+=+96\" but the base, b, = 32\", so substituting this for b, you have:
\n" ); document.write( "\"%281%2F2%29%2832%29h+=+96\" Solve for h.
\n" ); document.write( "\"16h+=+96\"
\n" ); document.write( "\"h+=+6\"inches.
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