document.write( "Question 222124: Train A and B are traviling the same direction on parallel tracks. Train A is traviling at 100 miles per hour and train B is traviling at 120 miles per hour. Train A passes a station at 5:25 p.m. If train B passes the same station at 5:40 p.m., at what time will train B catch up with train A? \n" ); document.write( "
Algebra.Com's Answer #166431 by ankor@dixie-net.com(22740)\"\" \"About 
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Train A and B are traveling the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour.
\n" ); document.write( " Train A passes a station at 5:25 p.m.
\n" ); document.write( " If train B passes the same station at 5:40 p.m., at what time will train B catch up with train A?
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\n" ); document.write( "from the given information, we know that train B is 15 min (.25 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .25 * 120 = 30 mi
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\n" ); document.write( "Let t = time required for train B to catch train a
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train b travel dist = Train a travel dist + 30 mi
\n" ); document.write( "120t = 100t + 30
\n" ); document.write( "120t - 100t = 30
\n" ); document.write( "20t = 30
\n" ); document.write( "t = \"30%2F20\"
\n" ); document.write( "t = 1.5 hr or 1 hr 30 min
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\n" ); document.write( "5:25 + 1:30 = 6:55 pm, B catches A
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\n" ); document.write( "Check solution by finding the distances (train b travels 30 mi more than train b)
\n" ); document.write( "120 * 1.5 = 180 mi
\n" ); document.write( "100 * 1.5 = 150 mi
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\n" ); document.write( "difference = 30 mi
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