document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29870>Question 29870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question: Solve 1/4=8^5x-4\r<BR>\n" );
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document.write( "POssible Four Answers:<BR>\n" );
document.write( "(1) 2/15\r<BR>\n" );
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document.write( "(2) 2/3\r<BR>\n" );
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document.write( "(3) 2/5\r<BR>\n" );
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document.write( "(4) 14/15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16642 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4=8^5x-4<BR>\n" );
document.write( "That ia 1/(2^2) = (2^3)^(5x-4)<BR>\n" );
document.write( "2^(-2) = 2^[3(5x-4)]  (using 1/(a^m)=(a)^(-m) and (a^m)^n = (a)^(mn) )<BR>\n" );
document.write( "(-2) = 3(5x-4) (when bases are the same the powers are equal)<BR>\n" );
document.write( "-2 = 15x-12<BR>\n" );
document.write( "-2+12 = 15x<BR>\n" );
document.write( "10 =15x<BR>\n" );
document.write( "That is 15x = 10<BR>\n" );
document.write( "Dividing by 15<BR>\n" );
document.write( "x = 10/15 = 2X5/3X5 = 2/3   (canceling 5)<BR>\n" );
document.write( "Answer: 2/3<BR>\n" );
document.write( "Which is your choice 2)<BR>\n" );
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