document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222132>Question 222132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can i graph a line that satisfies the conditions of passing through (2,-1) parallel to graph of 2x+3y=6\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166415 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> passing through (2,-1) parallel to graph of 2x+3y=6<BR>\n" );
document.write( "3Y=-2X+6<BR>\n" );
document.write( "Y=-2X/3+6/3<BR>\n" );
document.write( "Y=-2X/3+2 THIS LINE HAS A SLOPE = -2/3. THEREFORE A PARALLEL LINE WILL ALSO HAVE A SLOPE=-2/3<BR>\n" );
document.write( "-1=-2/3*2+b<BR>\n" );
document.write( "-1=-4/3+b<BR>\n" );
document.write( "b=-1+4/3<BR>\n" );
document.write( "b=-3/3+4/3<BR>\n" );
document.write( "b=1/3 the y intercept.<BR>\n" );
document.write( "y=-2x/3+1/3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-2x%2F3+%2B1%2F3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-2x%2F3+%2B1%2F3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 5, y from -10 to 10,-2x/3 +1/3). <BR>\n" );
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