document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222124>Question 222124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traviling the same direction on parallel tracks. Train A is traviling at 100 miles per hour and train B is traviling at 120 miles per hour. Train A passes a station at 5:25 p.m. If train B passes the same station at 5:40 p.m., at what time will train B catch up with train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166411 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100T=120(T-.25)<BR>\n" );
document.write( "100T=120T-30<BR>\n" );
document.write( "100T-120T=-30<BR>\n" );
document.write( "-20T=30<BR>\n" );
document.write( "T=-30/-20<BR>\n" );
document.write( "T=1.5 HOURS AFTER TRAIN A LEAVES THE STATION B TRAIN WILL CATCH UP.<BR>\n" );
document.write( "5:25+1:30=6:55 IS THE CATCH-UP HOUR.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );