document.write( "Question 222066: A row boat traveled 12 miles in 2 hours against the current. It traveled 18 miles in the same amount of time with the current. Find the rate of the boat in still water and ther rate of the current? \n" ); document.write( "
Algebra.Com's Answer #166374 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "If the boat went 12 miles in 2 hours, its rate against the current is 12 divided by 2 = 6 mph. Likewise, the rate with the current is 9 mph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The rate against the current is the still water speed minus the current speed. The rate with the current is the still water speed plus the current speed, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the two equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the speed of the boat in still water is 7.5 mph. The speed of the current is then\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |