document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=222056>Question 222056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this question. the measure of the supp. of an angle exceeds twice the measure of the comp. of the angle by 20. find the measure of 1/2 the comp.\r<BR>\n" );
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document.write( "is this how it is set up? 180-x= 2(90-x)+20<BR>\n" );
document.write( "please help... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166367 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You set it up right.  Now solve for x.\r<BR>\n" );
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document.write( "180-x=2(90-x)+20\r<BR>\n" );
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document.write( "180 - x = 180 -2x + 20\r<BR>\n" );
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document.write( "Subtract 180 from each side:<BR>\n" );
document.write( "-x=-2x+20\r<BR>\n" );
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document.write( "Add +2x to each side:\r<BR>\n" );
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document.write( "-x + 2x = -2x + 2x + 20<BR>\n" );
document.write( "x= 20\r<BR>\n" );
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document.write( "Now, answer the question.  Find one half of the complement of the angle.\r<BR>\n" );
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document.write( "The angle was 20 degrees, so the complement of this angle would be 70.  Now, half of 70 is 35 degrees.  Does that look right?\r<BR>\n" );
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document.write( "R^2\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje </SPAN>\n" );
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