document.write( "Question 221964: part of $12,000 investment earned interest at a rate of 7% and the rest earned interest at a rate of 9%. the combined interest earned at the end of 1 year was $890. how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #166337 by checkley77(12844) ![]() You can put this solution on YOUR website! .09x+.07(12,000-x)=890 \n" ); document.write( ".09x+840-.07x=890 \n" ); document.write( ".02x=890-840 \n" ); document.write( ".02x=50 \n" ); document.write( "x=50/.02 \n" ); document.write( "x=2,500 amount invested @ 9%. \n" ); document.write( "12,000-2,500=9,500 invested @ 7%. \n" ); document.write( "Proof: \n" ); document.write( ".09*2,500+.07*9,500=890 \n" ); document.write( "225+665=890 \n" ); document.write( "890=890 \n" ); document.write( " |