document.write( "Question 221975: a hospital needs 80 L of a 12% solution of disinfectant. how many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution? \n" ); document.write( "
Algebra.Com's Answer #166326 by checkley77(12844) ![]() You can put this solution on YOUR website! .33x+.05(80-x)=.12*80 \n" ); document.write( ".33x+4-.05x=9.6 \n" ); document.write( ".33x-.05x=9.6-4 \n" ); document.write( ".28x=5.6 \n" ); document.write( "x=5.6/.28 \n" ); document.write( "x=20 L of 33% solution is used. \n" ); document.write( "80-20=60 L of 5% solution is used. \n" ); document.write( "Proof: \n" ); document.write( ".33*20+.05*60=.12*80 \n" ); document.write( "6.6+3=9.6 \n" ); document.write( "9.6=9.6 \n" ); document.write( " \n" ); document.write( " |