document.write( "Question 221983: Hello, I am trying to figure out if I am on the right track. For some reason I just can't understand how to factor. Thanks in advance.\r
\n" ); document.write( "\n" ); document.write( "2t^2 y^4 - 32t^2 (I think at this point I can factor out the t^2)\r
\n" ); document.write( "\n" ); document.write( "t^2 (2y^4 - 32) (do I factor the parentheses at this point? I'm not sure where to go from here.)
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Algebra.Com's Answer #166317 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Missed it by THAT much.\r
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\n" ); document.write( "\n" ); document.write( "Factoring out the was certainly the right thing to do, but if you notice, the numerical coefficients on the two original terms have the factor 2 in common. Hence, the correct first step would have been to factor out leaving you with:\r
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\n" ); document.write( "\n" ); document.write( "But you aren't done, not by a long shot.\r
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\n" ); document.write( "\n" ); document.write( "Notice that is the difference of two squares, so:\r
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\n" ); document.write( "\n" ); document.write( "And then notice that is also the difference of two squares, so:\r
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\n" ); document.write( "\n" ); document.write( "And that's as far as you can go presuming you are confining yourself to the real numbers.\r
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