document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3805>Question 3805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would like an algebra expression for the following problem:\r<BR>\n" );
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document.write( "A number increased by 8 is the difference of the number and a product of the number multiplied by-4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1663 by </B><A HREF=/tutors/aboutme.mpl?userid=WannabeCAgirl83><B>WannabeCAgirl83(35)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=WannabeCAgirl83><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the unknown number: x<BR>\n" );
document.write( "the unknown number increased by 8: x + 8<BR>\n" );
document.write( "a product of the unknown number multiplied by -4: - 4x\r<BR>\n" );
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document.write( "If x + 8 is the difference between x and - 4x, then x + (x + 8) is equal to - 4x, so... \r<BR>\n" );
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document.write( "x + (x + 8) = - 4x | re-arranging<BR>\n" );
document.write( "2x + 8 = - 4x | - 2x on both sides<BR>\n" );
document.write( "8 = -6x | : -6 on both sides<BR>\n" );
document.write( "- 1 1/3 = x<BR>\n" );
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