document.write( "Question 221798: Please help me solve this problem...I dont know how to start solving this..\r
\n" ); document.write( "\n" ); document.write( "A 10-quart container is filled with water. One quart of water is drained out and replaced with alcohol. After mixing, a quart of the soluti0n is drained out and replaced with alcohol. This process continued until 5quarts of alcohol have been put into the container. The solution in the container is then what percent of alcohol?\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance..
\n" ); document.write( "

Algebra.Com's Answer #166271 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A 10-quart container is filled with water.
\n" ); document.write( "One quart of water is drained out and replaced with alcohol.
\n" ); document.write( "After mixing, a quart of the soluti0n is drained out and replaced with alcohol.
\n" ); document.write( " This process continued until 5quarts of alcohol have been put into the container.
\n" ); document.write( " The solution in the container is then what percent of alcohol?
\n" ); document.write( ":
\n" ); document.write( "try it step by step
\n" ); document.write( ":
\n" ); document.write( "After the 1st replacement, its a .1(10) mixture
\n" ); document.write( ":
\n" ); document.write( "2nd replacement:
\n" ); document.write( ".1(10-1) + 1 =
\n" ); document.write( ".1(9) + 1 =
\n" ); document.write( ".9 + 1 = 1.9 = 1.9 qt of alcohol
\n" ); document.write( "that's a \"1.9%2F10\" = .19(10) mixture
\n" ); document.write( ":
\n" ); document.write( "3rd replacement
\n" ); document.write( ".19(10-1) + 1
\n" ); document.write( ".19(9) + 1
\n" ); document.write( "1.71 + 1 = 2.71 qt of alcohol
\n" ); document.write( "that's \"2.71%2F10\" = .27(10) mixture
\n" ); document.write( ":
\n" ); document.write( "3rd replacement
\n" ); document.write( ".27(10-1) + 1 =
\n" ); document.write( ".27(9) + 1 =
\n" ); document.write( "2.44 + 1 = 3.44 gt of alcohol
\n" ); document.write( "that's \"3.44%2F10\" = .344(10) mixture
\n" ); document.write( ":
\n" ); document.write( "4th replacement
\n" ); document.write( ".344(10-1) + 1 =
\n" ); document.write( ".344(9) + 1 =
\n" ); document.write( "3.096 + 1 = 4.096 gt of alcohol
\n" ); document.write( "that's \"4.096%2F10\" = .4096(10) mixture
\n" ); document.write( ":
\n" ); document.write( "5th replacement
\n" ); document.write( ".4096(10-1) + 1 =
\n" ); document.write( ".4096(9) + 1 =
\n" ); document.write( "3.6864 + 1 = 4.6864 qt of alcohol
\n" ); document.write( "that's \"4.6864%2F10\" = .46864(10) mixture
\n" ); document.write( ":
\n" ); document.write( "we can say 46.864% alcohol now
\n" ); document.write( "
\n" );