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15x+3y=90 ----(1)
\n" ); document.write( "3y = -15x+90
\n" ); document.write( "Dividing through out by 3
\n" ); document.write( "y = (-5)x+30 ----(*)
\n" ); document.write( "(*) is in the standard slope and y-intercept form:
\n" ); document.write( "y = (m)x + b wher m is the slope and b is the y-intercept
\n" ); document.write( "Therefore slope of the given line is (-5)
\n" ); document.write( "And y-intercept = 30
\n" ); document.write( "Note: Given the equation of a straight line
\n" ); document.write( "in the general form Ax+By+C=0,
\n" ); document.write( "then the slope is given by (-A/B) (if you can remember )
\n" ); document.write( "According to this
\n" ); document.write( "in the given line (15)x+(3)y-90 =0,
\n" ); document.write( "the slope = (-A/B) = -15/3 = -5
\n" ); document.write( "Note: Given the line in the general form Ax+By+C=0,
\n" ); document.write( "how to convert it into the slope and y-intercept form?
\n" ); document.write( "Retain the y-term on the left and take the other terms to the right side.
\n" ); document.write( "Divide through out by the coefficient of y.
\n" ); document.write( "When the coefficient of y is 1 on the LHS, the coefficient of x on the RHS gives the slope of the line and the free constant now on the RHS
\n" ); document.write( "gives the y-intercept. \n" ); document.write( "