document.write( "Question 29860: I am working with parabolas. For this problem I need to
\n" ); document.write( "Complete the square
\n" ); document.write( "Give the Vertex
\n" ); document.write( "Give the Axis
\n" ); document.write( "Give the x-intercepts
\n" ); document.write( "Give the y-intercepts
\n" ); document.write( "Give a point symmetric to the y-intercept
\n" ); document.write( "Draw the graph
\n" ); document.write( "The problem is y=x^2-2x-3.
\n" ); document.write( "Can anyone help me solve this. I am working on it and would like to have something to check my answer with.
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Algebra.Com's Answer #16624 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
SEE THE FOLLOWING EXAMPLE WHICH IS ALMOST SAME AS YOUR PROBLEM AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK.
\n" ); document.write( "Y=X^2-2X-3=X^2-2*X*1+1^2-1-3=(X-1)^2-1-3=(X-1)^2-4=0
\n" ); document.write( "X INTERCEPT IS OBTAINED BY PUTTING Y=0....WE GET
\n" ); document.write( "X^2-2X-3=0=X^2-3X+X-3=X(X-3)+1(X-3)=(X-3)(X+1)=0...SO..X=3 OR -1...
\n" ); document.write( "Y INTERCEPT IS GOT BY PUTTING X =0...WE GET
\n" ); document.write( "Y=0-0-3=-3
\n" ); document.write( "SEE THE GRAPH BELOW ......
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+20%2C+-20%2C+20%2Cx%5E2-2x-3+%29+\"
\n" ); document.write( "THE AXIS IS X=1 AS YOU CAN SEE FROM THE GRAPH
\n" ); document.write( "ONE POINT SYMMETRIC TO Y INTERCEPT??NO...SYMMETRIC TO AXIS IT IS......(-1,3)
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\n" ); document.write( "\n" ); document.write( "I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k.
\n" ); document.write( "MAKE A PERFECT SQUARE USING X^2 AND X TERMS.ADD AND SUBTRACT THE REQUIRED CONSTANT FOR THE PURPOSE.
\n" ); document.write( "Y=(X-1)^2-1-15=(X-1)^2-16...COMPARING WITH THE ABOVE
\n" ); document.write( "y=a(x-h)^2+k.
\n" ); document.write( "WE GET A=1 AND K=-16
\n" ); document.write( " I have to find the line of symmetry.
\n" ); document.write( "X-1=0 IS THE LINE OF SYMMETRY SINCE ON EITHER SIDE OF X=1,WE GET SYMMETRIC/SAME VALUES FOR Y..AT X=1+2=3..Y IS -12 AND AT X=1-2=-1 ALSO WE GET Y=-12
\n" ); document.write( " (h,k)=vertex I think you use complete the square technique.
\n" ); document.write( "YA ..THE VERTEX AS YOU SHOULD KNOW NOW IS AT X=1 AND AT X=1 ,Y=-16 .SO (1,-16) IS THE VERTEX
\n" ); document.write( "THE GRAPH WILL LOOK LIKE THIS
\n" ); document.write( " \"+graph%28+500%2C+500%2C+-10%2C+20%2C+-20%2C+20%2C+x%5E2-2x-15+%29+\"
\n" ); document.write( " Please help. thanks
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