document.write( "Question 29860: I am working with parabolas. For this problem I need to
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document.write( "Complete the square
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document.write( "Give the Vertex
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document.write( "Give the Axis
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document.write( "Give the x-intercepts
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document.write( "Give the y-intercepts
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document.write( "Give a point symmetric to the y-intercept
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document.write( "Draw the graph
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document.write( "The problem is y=x^2-2x-3.
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document.write( "Can anyone help me solve this. I am working on it and would like to have something to check my answer with. \n" );
document.write( "
Algebra.Com's Answer #16624 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING EXAMPLE WHICH IS ALMOST SAME AS YOUR PROBLEM AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK. \n" ); document.write( "Y=X^2-2X-3=X^2-2*X*1+1^2-1-3=(X-1)^2-1-3=(X-1)^2-4=0 \n" ); document.write( "X INTERCEPT IS OBTAINED BY PUTTING Y=0....WE GET \n" ); document.write( "X^2-2X-3=0=X^2-3X+X-3=X(X-3)+1(X-3)=(X-3)(X+1)=0...SO..X=3 OR -1... \n" ); document.write( "Y INTERCEPT IS GOT BY PUTTING X =0...WE GET \n" ); document.write( "Y=0-0-3=-3 \n" ); document.write( "SEE THE GRAPH BELOW ...... \n" ); document.write( " \n" ); document.write( "THE AXIS IS X=1 AS YOU CAN SEE FROM THE GRAPH \n" ); document.write( "ONE POINT SYMMETRIC TO Y INTERCEPT??NO...SYMMETRIC TO AXIS IT IS......(-1,3) \n" ); document.write( "******************************************************************************\r \n" ); document.write( "\n" ); document.write( "I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k. \n" ); document.write( "MAKE A PERFECT SQUARE USING X^2 AND X TERMS.ADD AND SUBTRACT THE REQUIRED CONSTANT FOR THE PURPOSE. \n" ); document.write( "Y=(X-1)^2-1-15=(X-1)^2-16...COMPARING WITH THE ABOVE \n" ); document.write( "y=a(x-h)^2+k. \n" ); document.write( "WE GET A=1 AND K=-16 \n" ); document.write( " I have to find the line of symmetry. \n" ); document.write( "X-1=0 IS THE LINE OF SYMMETRY SINCE ON EITHER SIDE OF X=1,WE GET SYMMETRIC/SAME VALUES FOR Y..AT X=1+2=3..Y IS -12 AND AT X=1-2=-1 ALSO WE GET Y=-12 \n" ); document.write( " (h,k)=vertex I think you use complete the square technique. \n" ); document.write( "YA ..THE VERTEX AS YOU SHOULD KNOW NOW IS AT X=1 AND AT X=1 ,Y=-16 .SO (1,-16) IS THE VERTEX \n" ); document.write( "THE GRAPH WILL LOOK LIKE THIS \n" ); document.write( " \n" ); document.write( " Please help. thanks \n" ); document.write( " |