document.write( "Question 221734: negative 4z to the 6th y to the 3rd over
\n" ); document.write( "negative 16z to the 7th y to the negative 2 and all to the negative 3rd \n" ); document.write( "
Algebra.Com's Answer #166239 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"%28%28-4z%5E6y%5E3%29%2F%28-16z%5E7y%5E%28-2%29%29%29%5E%28-3%29\"
\n" ); document.write( "NOTE: If this is not your problem, please repost it with parentheses around
  • each numerator
  • each denominator
  • each expression to which an exponent applies

\n" ); document.write( "Since there is only one term in both the numerator and denominator and since \"%28a%2Ab%2Ac%29%2F%28d%2Ae%2Af%29+=+%28a%2Fd%29%2A%28b%2Fe%29%2A%28c%2Ff%29\", we can simplify the fraction factor by factor:
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\n" ); document.write( "Reducing the first fraction and using the rule for division with exponents: \"%28x%5Ea%29%2F%28x%5Eb%29+=+x%5E%28a-b%29\" on the other two we get:
\n" ); document.write( "\"%28%281%2F4%29%2Az%5E%28-1%29%2Ay%5E5%29%5E%28-3%29\"
\n" ); document.write( "Another rule of exponents (which I call the \"pseudo\" (or fake) distributive property) is: \"%28a%2Ab%29%5Ec+=+a%5Ec%2Ab%5Ec\" allows us to \"distribute\" the exponent to each factor. (IMPORTANT: This fake distributive property does not apply if there is more than one term in the parentheses. For example \"%28x%2By%29%5En+%3C%3E+x%5En+%2B+y%5En\"!!!)
\n" ); document.write( "\"%281%2F4%29%5E%28-3%29%2A%28z%5E%28-1%29%29%5E%28-3%29%2A%28y%5E5%29%5E%28-3%29\"
\n" ); document.write( "On the first fraction we'll use the property: \"x%5E%28-n%29+=+1%2Fx%5En\".
\n" ); document.write( "\"%284%2F1%29%5E%283%29%2A%28z%5E%28-1%29%29%5E%28-3%29%2A%28y%5E5%29%5E%28-3%29\"
\n" ); document.write( "We can cube 4 and use another rule for exponents (power of a power) on the other two: \"%28x%5Ea%29%5Eb+=+x%5E%28a%2Ab%29\"
\n" ); document.write( "\"64z%5E3y%5E%28-15%29\" \n" ); document.write( "
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