document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221735>Question 221735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the complex number a + bi such that 5a + 3b = 1 and -5a = 7 + 4a  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166225 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5a + 3b = 1 and -5a = 7 + 4a \r<BR>\n" );
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document.write( "From the second equation, <BR>\n" );
document.write( "-9a=7<BR>\n" );
document.write( "a=-7/9\r<BR>\n" );
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document.write( "Back into the first equation:\r<BR>\n" );
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document.write( "5a+3b=1<BR>\n" );
document.write( "5(-7/9)+3b=1<BR>\n" );
document.write( "-35/9 +3b=1\r<BR>\n" );
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document.write( "-35/9+35/9+3b=1+35/9<BR>\n" );
document.write( "3b=9/9+35/9<BR>\n" );
document.write( "3b=44/9<BR>\n" );
document.write( "b=44/27\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2Bbi=-7%2F9%2B%2844%2F27%29i ALIGN=MIDDLE  ALT=\"a%2Bbi=-7%2F9%2B%2844%2F27%29i\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2<BR>\n" );
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