document.write( "Question 221733: if you row 360 feet against the current in 6 minutes and 500 feet with the current in 5 minutes how fast is the current? \n" ); document.write( "
Algebra.Com's Answer #166223 by rapaljer(4671)\"\" \"About 
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Let x= speed in still water
\n" ); document.write( "c= speed of current
\n" ); document.write( "Rate = Dist/Time\r
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\n" ); document.write( "\n" ); document.write( "x+c = rate with the stream= 500 feet/5 min
\n" ); document.write( "x-c= rate against the stream=360 feet/6 min\r
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\n" ); document.write( "\n" ); document.write( "x+c=100
\n" ); document.write( "x-c=60\r
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\n" ); document.write( "\n" ); document.write( "Add the equations together:
\n" ); document.write( "2x=160
\n" ); document.write( "x=80 ft/min= speed in still water\r
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\n" ); document.write( "\n" ); document.write( "x+c=100
\n" ); document.write( "80+c=100
\n" ); document.write( "c=20 ft/min= speed of current\r
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\n" ); document.write( "\n" ); document.write( "R^2\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje
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