document.write( "Question 221733: if you row 360 feet against the current in 6 minutes and 500 feet with the current in 5 minutes how fast is the current? \n" ); document.write( "
Algebra.Com's Answer #166223 by rapaljer(4671) You can put this solution on YOUR website! Let x= speed in still water \n" ); document.write( "c= speed of current \n" ); document.write( "Rate = Dist/Time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+c = rate with the stream= 500 feet/5 min \n" ); document.write( "x-c= rate against the stream=360 feet/6 min\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+c=100 \n" ); document.write( "x-c=60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the equations together: \n" ); document.write( "2x=160 \n" ); document.write( "x=80 ft/min= speed in still water\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+c=100 \n" ); document.write( "80+c=100 \n" ); document.write( "c=20 ft/min= speed of current\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje \n" ); document.write( " |