document.write( "Question 221674: The new Twinkle bulb has a standard deviation 34 hours. A random sample of 77 light bulbs is selected from inventory. The sample mean was found to be 492 hours. Find the margin of error E for a 90% confidence interval. Round your answer to the nearest hundredths. Then I have to construct a 90% confidence interval for the mean life. I know how to do that part I just can't figure out the first part. The sqrt gets me. \n" ); document.write( "
Algebra.Com's Answer #166210 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The new Twinkle bulb has a standard deviation 34 hours. \n" ); document.write( "A random sample of 77 light bulbs is selected from inventory. \n" ); document.write( "The sample mean was found to be 492 hours. \r \n" ); document.write( "\n" ); document.write( "Find the margin of error E for a 90% confidence interval. Round your answer to the nearest hundredths. \r \n" ); document.write( "\n" ); document.write( "Then I have to construct a 90% confidence interval for the mean life. \r \n" ); document.write( "\n" ); document.write( "I know how to do that part I just can't figure out the first part. The sqrt gets me. \n" ); document.write( "--------------------------------------- \n" ); document.write( "invT(0.05,76) = -1.6652 \n" ); document.write( "------------ \n" ); document.write( "E = 1.6652[34/sqrt(77)] = 6.4519 \n" ); document.write( "------------------------------------------- \n" ); document.write( "90% CI: 492 - 6.4519 < u < 492 + 6.4519 \n" ); document.write( "================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |