document.write( "Question 3804: Can you help me solve this Linear Equation\r
\n" ); document.write( "\n" ); document.write( "x-5y=-154
\n" ); document.write( "x-3y=-84
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Algebra.Com's Answer #1662 by WannabeCAgirl83(35)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "There you go... ;-)\r
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\n" ); document.write( "\n" ); document.write( "x – 5y = - 154 (Lets name this Equation 1)
\n" ); document.write( "x – 3y = - 84 (Lets name this Equation 2)\r
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\n" ); document.write( "\n" ); document.write( "Step # 1
\n" ); document.write( "Isolating x in Equation 1:\r
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\n" ); document.write( "\n" ); document.write( "x – 5y = - 154
\n" ); document.write( "x – 5y = - 154 | + 5y on both sides
\n" ); document.write( "x = - 154 + 5y\r
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\n" ); document.write( "\n" ); document.write( "Step # 2
\n" ); document.write( "Substituting x in Equation 2 with the term found for x in step # 1, then isolating y :\r
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\n" ); document.write( "\n" ); document.write( "x – 3y = - 84
\n" ); document.write( "- 154 + 5y – 3y = - 84 | re-arranging
\n" ); document.write( "- 154 + 2y = - 84 | + 154 on both sides
\n" ); document.write( "2y = 70 | : 2 on both sides
\n" ); document.write( "y = 35\r
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\n" ); document.write( "\n" ); document.write( "Step # 3
\n" ); document.write( "Substituting y in Equation 1 with the term found for y in step # 2, then again isolating x :\r
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\n" ); document.write( "\n" ); document.write( "x – 5y = - 154
\n" ); document.write( "x – 5(35) = - 154
\n" ); document.write( "x – 175 = - 154 | + 175 on both sides
\n" ); document.write( "x = 21\r
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\n" ); document.write( "\n" ); document.write( "Step # 4:
\n" ); document.write( "Validating solutions by substituting them with x and y in both Equations:\r
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\n" ); document.write( "\n" ); document.write( "x – 5y = - 154
\n" ); document.write( "21 – 5(35) = -154 → true \r
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\n" ); document.write( "\n" ); document.write( "x – 3y = - 84
\n" ); document.write( "21 – 3(35) = - 84 → true
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