document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221344>Question 221344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Add &#8730;(9y + 27) + &#8730;(y + 3)\r<BR>\n" );
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document.write( "I dont know where to even begin..  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166172 by </B><A HREF=/tutors/aboutme.mpl?userid=likaaka><B>likaaka(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=likaaka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are working with 2 terms here and you want to simplify to one term.<BR>\n" );
document.write( "Begin by factoring out the 9 from under the radical in the first term<BR>\n" );
document.write( "&#8730;(9y + 27) becomes  &#8730;(9y/9 + 27/9), now simplify<BR>\n" );
document.write( "&#8730;9(y + 3) + &#8730;(y + 3), in the first term 9 is an even root and can be moved to the outside of the radical<BR>\n" );
document.write( "(&#8730;9)(&#8730;(y + 3)) + &#8730;(y + 3), simplify the square root of 9 is 3<BR>\n" );
document.write( "3&#8730;(y + 3) + &#8730;(y + 3), now combine like terms. There's actually a 1 in front of the second term so add together<BR>\n" );
document.write( "3&#8730;(y + 3) + 1&#8730;(y + 3)<BR>\n" );
document.write( "4&#8730;(y + 3) </SPAN>\n" );
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